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srn4 - n/a
3-Apr-06, 08:28 PM
Does anyone know how to calculate the force in Newtons which pulls the pulleys together as an HTD belt is accelerated as I need this figure to allow me to work out how safe my current setup is?



An esimation is 500N, but I would like to have a more accurate figure to work with http://hovercraft.org.uk/images/icons/smiley_icons/icon_rolleyes.gif



Dunc

tonybroad - n/a
3-Apr-06, 09:01 PM
If you know the torque of your engine you can use



Torque (Nm) = Force(N) x Distance (radius of your pulley in metres)



so Torque/Distance = Force



35Nm with a 50mm diameter pulley gives me about 1400N



hope that helps



Tony

BIGRACING - n/a
4-Apr-06, 04:27 AM
Here are some numbers my computer could come up with:

index.php?t=getfile&id=177&private=0index.php?t=getfile&id=178&private=0

index.php?t=getfile&id=182&private=0

Load Rating for Bearings



Bearings - Basic dynamic load rating (www.bearings.machinedesign.com/guiEdits/Content/BDE_6_2/bdemech6_35.aspx)

Technical Section (www.qbcbearings.com/B605/qbctech15.htm)

Understanding Bearings for the Fan Industry (www.rlcraigco.com/Bearings.htm)

Nick Long - n/a
4-Apr-06, 08:54 AM
If you know the torque of your engine you can use



Torque (Nm) = Force(N) x Distance (radius of your pulley in metres)



so Torque/Distance = Force








And if you don't know the torque but do know the power being transmitted, then



Force(N) = Power(Watts) / Velocity(m/s)

where

Velocity(m/s) = Revs(rpm) x 60 x 2 x pi x radius(m)



Note that the Force derived by either method is strictly the differential tension between the two sides of the belt. If the return side is close to slack then the Force is the RADIAL load on the bearings.



The AXIAL load on the fan bearing is the thrust; on the other end the axial load will be low.



Nick